8x^2+5x=3=7x

Solution for 8x^2+5x=3=7x equation:

8x^2+5x=3=7x

We move all terms to the left:

8x^2+5x-(3)=0

a = 8; b = 5; c = -3;
Δ = b2-4ac
Δ = 52-4·8·(-3)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-11}{2*8}=\frac{-16}{16}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+11}{2*8}=\frac{6}{16}
=3/8
$